Capacitor Bank Calculation
A Capacitor Bank is a group of several capacitors of the same rating that are connected in series or parallel with each other to store electrical energy . The resulting bank is then used to counteract or correct a power factor lag or phase shift in an alternative current (AC) power supply.
The selection of the capacitor bank can be explained with an example as follows
Things to Remember
=√(1-0.75²)
0.75
= 0.882
Tan θ2 = √( 1- Cos² θ2)
Cos θ2
=√(1-0.95²)
0.95
= 0.3286
Required Capacitor Bank = 1500 ( 0.882-0.3286 )
A Capacitor Bank is a group of several capacitors of the same rating that are connected in series or parallel with each other to store electrical energy . The resulting bank is then used to counteract or correct a power factor lag or phase shift in an alternative current (AC) power supply.
The selection of the capacitor bank can be explained with an example as follows
Things to Remember
Tan θ = Sin θ / Cos θ
Sin θ = √( 1- Cos² θ)
Required Capacitor Bank, KVAR= Total Connected Load X ( Tan θ1 - Tan θ2)
Example
Consider the Existing Load = 1500 KW
Existing power Factor pf1, Cos θ1 = 0.75
Power Factor to be Obtained pf2, Cos θ2= 0.95
Tan θ1 = √( 1- Cos² θ1)
Cos θ1=√(1-0.75²)
0.75
= 0.882
Tan θ2 = √( 1- Cos² θ2)
Cos θ2
=√(1-0.95²)
0.95
= 0.3286
Required Capacitor Bank = 1500 ( 0.882-0.3286 )
= 830.1kVAR
Note: Those who don't want to make all these simple calculations, Please download the excel file from the below link and enter the values to get the result.
